-16t^2=-1/2

Solution for -16t^2=-1/2 equation:

-16t^2=-1/2

We move all terms to the left:

-16t^2-(-1/2)=0

We get rid of parentheses

-16t^2+1/2=0

We multiply all the terms by the denominator


-16t^2*2+1=0

Wy multiply elements

-32t^2+1=0

a = -32; b = 0; c = +1;
Δ = b2-4ac
Δ = 02-4·(-32)·1
Δ = 128
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{128}=\sqrt{64*2}=\sqrt{64}*\sqrt{2}=8\sqrt{2}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{2}}{2*-32}=\frac{0-8\sqrt{2}}{-64}
=-\frac{8\sqrt{2}}{-64}
=-\frac{\sqrt{2}}{-8}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{2}}{2*-32}=\frac{0+8\sqrt{2}}{-64}
=\frac{8\sqrt{2}}{-64}
=\frac{\sqrt{2}}{-8}
$